Parse an expression
An arithmetical expression consists of 2 numbers and an operator between them, for instance:
1 + 21.2 * 3.4-3 / -6-2 - 2
The operator is one of: "+", "-", "*" or "/".
There may be extra spaces at the beginning, at the end or between the parts.
Create a function parse(expr) that takes an expression and returns an array of 3 items:
- The first number.
- The operator.
- The second number.
For example:
let [a, op, b] = parse("1.2 * 3.4");
alert(a); // 1.2
alert(op); // *
alert(b); // 3.4
A regexp for a number is: -?\d+(\.\d+)?. We created it in previous tasks.
An operator is [-+*/]. The hyphen - goes first in the square brackets, because in the middle it would mean a character range, while we just want a character -.
The slash / should be escaped inside a JavaScript regexp /.../, we’ll do that later.
We need a number, an operator, and then another number. And optional spaces between them.
The full regular expression: -?\d+(\.\d+)?\s*[-+*/]\s*-?\d+(\.\d+)?.
It has 3 parts, with \s* between them:
-?\d+(\.\d+)?– the first number,[-+*/]– the operator,-?\d+(\.\d+)?– the second number.
To make each of these parts a separate element of the result array, let’s enclose them in parentheses: (-?\d+(\.\d+)?)\s*([-+*/])\s*(-?\d+(\.\d+)?).
In action:
let regexp = /(-?\d+(\.\d+)?)\s*([-+*\/])\s*(-?\d+(\.\d+)?)/;
alert( "1.2 + 12".match(regexp) );
The result includes:
result[0] == "1.2 + 12"(full match)result[1] == "1.2"(first group(-?\d+(\.\d+)?)– the first number, including the decimal part)result[2] == ".2"(second group(\.\d+)?– the first decimal part)result[3] == "+"(third group([-+*\/])– the operator)result[4] == "12"(forth group(-?\d+(\.\d+)?)– the second number)result[5] == undefined(fifth group(\.\d+)?– the last decimal part is absent, so it’s undefined)
We only want the numbers and the operator, without the full match or the decimal parts, so let’s “clean” the result a bit.
The full match (the arrays first item) can be removed by shifting the array result.shift().
Groups that contain decimal parts (number 2 and 4) (.\d+) can be excluded by adding ?: to the beginning: (?:\.\d+)?.
The final solution:
function parse(expr) {
let regexp = /(-?\d+(?:\.\d+)?)\s*([-+*\/])\s*(-?\d+(?:\.\d+)?)/;
let result = expr.match(regexp);
if (!result) return [];
result.shift();
return result;
}
alert( parse("-1.23 * 3.45") ); // -1.23, *, 3.45